第四章 向量组的线性相关性 1? 设v1?(1? 1? 0)T? v2?(0? 1? 1)T? v3?(3? 4? 0)T? 求v1?v2及3v1?2v2?v3? 解 v1?v2?(1? 1? 0)T?(0? 1? 1)T ?(1?0? 1?1? 0?1)T ?(1? 0? ?1)T? 3v1
线性代数 同济大学 第四版课后答案习题一(1)(2)(3)(4)(1)(2)(3)(4)(5)(6)(1)(2)(3)(4)习题二(1)(2)(3)习题三习题四习题五习题六Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :
线性代数答案解答第一章 行列式1.利用对角线法则计算下列三阶行列式:.解(2)(4)2.按自然数从小到大为标准次序求下列各排列的逆序数:解(4)逆序数为3:2 14 14 3(6)逆序数为3 2 1个5 25 4
第一章 行列式 1? 利用对角线法则计算下列三阶行列式? (1)? 解 ?2?(?4)?3?0?(?1)?(?1)?1?1?8 ?0?1?3?2?(?1)?8?1?(?4)?(?1) ??24?8?16?4??4? (2)? 解 ?acb?bac?cba?bbb?aaa?ccc
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
第一章 行列式 1? 利用对角线法则计算下列三阶行列式? (1)? 解 ?2?(?4)?3?0?(?1)?(?1)?1?1?8 ?0?1?3?2?(?1)?8?1?(?4)?(?1) ??24?8?16?4??4? (2)? 解 ?acb?bac?cba?bbb?aaa?ccc
单击此处编辑母版标题样式单击此处编辑母版文本样式第二级第三级第四级第五级定义1分量全为复数的向量称为复向量.分量全为实数的向量称为实向量一 维向量的概念例如n维实向量n维复向量第1个分量第n个分量第2个分量二 维向量的表示方法 维向量写成一行称为行向量也就是行矩阵通常用 等表示如: 维向量写成一列称为列向量也就是列矩阵通常用 等表示如:注意 1.行向量和列向量总
第四章 Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
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