解方程6x-×6 = 118-2×( X ) = 55 4x 80 = 160 ÷X = -X = 3×( X 6 ) - = - =
(1)98998999899998=(100-2)(1000-2)(10000-2)(10000-2)=10010001000010000-2-2-2-2=111100-8=111092(2)11271123=(11207)(11203)=11201120112031120773=12544001120(73)21=12544001120021=1265621 脱式计算 408-12×24
22×4221 21×3410 40÷217414772÷8 9×4420 2×80÷4120×5÷2 20236÷9 30÷524081÷9877 66×5774 9217×480×
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脱式计算: 360÷[(126)×5] 288÷[(26-14)×8] 500×6-(50×2-80) (105×12-635)÷25 864÷[(27-23)×12] (4538-16)×24 500-(24038×6) [64-(87-42)] ×15 (845-15×3)÷1612×[(49-28)÷7] 450÷[(84-48] )÷12 (5837)÷(64-9×5) 95÷(64-45
五年级上册脱式计算解方程应用题脱式计算288÷[(26-14)×8]? 500×6-(50×2-80)?(105×12-635)÷25? 864÷[(27-23)×12]?(4538-16)×24? 500-(24038×6)?[6
暑 假 脱 式 计 算:郗悦彤82118-99 ÷7÷ 5× x-6×5=42 14X-8X=12 6×52X=×4× 50×420 ÷-21 20X-50= 50 286X=88 32-22X=10100×× ÷319
1催化剂体积估算2催化剂层数估算3反应器高度估算尿素消耗量估算公式 氮氧化物脱除量68601.5液氨消耗量估算 氮氧化物脱除量30171.5Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.as
Evaluation Only. Created with Aspose.Words. Copyright 2003-2022 Aspose Pty Ltd.方程式计算1在一定条件下在一个密闭容器内发生某反应测得反应过程中各物质的质量如下表所示下列说法不正确的是 物质 ? X? Y? Z? W反应前质量 g ?
21230×76 25232×83 71728×73 = = = = = = 93972×29 56536×83 65688×35 =
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