已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB5已知:ABED∠EAB=∠BDEAF=CDEF=BC求证:∠F=∠CDCBAFE6如图已知ABDCACDBBECE求证:AED
已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:D是AB中点∠ACB=90°求证:DABC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE已知:AB
已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:D是AB中点∠ACB=90°求证:DABC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE已知:AB=4A
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全等三角形经典证明已知:AB=10AC=2D是BC中点AD是整数求AD延长AD到E使DE=AD则三角形ADC全等于三角形EBD即BE=AC=2 在三角形ABE中AB-BE<AE<ABBE即:10-2<2AD<102 4<AD<6又AD是整数则AD=5?1. 已知:D是AB中点∠ACB=90°求证:CDB D 1AB 22. 已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2证明:连接
已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:D是AB中点∠ACB=90°求证:DABC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE已知:AB
已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE12. 如图四边形ABCD中AB∥DCBECE分别平分∠ABC∠BCD且点E在AD上求证:BC=ABDC13.已知:ABED∠EAB=∠BDEAF=CDEF=BC求证:∠F=∠CDC
已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:D是AB中点∠ACB=90°求证:DABC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE已知:AB
已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:D是AB中点∠ACB=90°求证:DABC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE已知:AB
已知:AB=4AC=2D是BC中点AD是整数求ADADBC已知:D是AB中点∠ACB=90°求证:DABC已知:BC=DE∠B=∠E∠C=∠DF是CD中点求证:∠1=∠2ABCDEF21已知:∠1=∠2CD=DEEFAB求证:EF=ACBACDF21E已知:AD平分∠BACAC=ABBD求证:∠B=2∠CACDB已知:AC平分∠BADCE⊥AB∠B∠D=180°求证:AE=ADBE已知:AB
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