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求任意一个数的阶乘求5的阶乘我们先来求5的阶乘再扩展到求任意一个数的阶乘这样就容易掌握求阶乘的方法了首先要理解一下阶乘的公式 n =n(n-1)(n-2)....21 5 = 54321include<>int main(){int t=5i=4 要是求其他的数的阶乘的话把t的值改为其他数 再把i改为(t-1)就行了while(i>=1){t=tii-
打印乘法口诀表程序求阶乘程序实现循环结构乘法口诀表11=121=231=341=451=561=671=781=891=912=222=432=642=852=1062=1272=1482=1692=1813=323=633=943=1253=1563=1873=2183=2493=2714=424=834=1244=1654=2064=2474=2884=3294=3615=525=1035=1
template <class T>class Chaintemplate <class T>class ChainNode{friend Chain <T>:private:T dateChainNode <T> link}template <class T>class Chain{public:Chain(){first = 0}Chain()bool IsEmpty() const {ret
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源程序:DATAS SEGMENTSTR1DB0AH 0DH ----------------------------------------- DB0AH 0DH Get nDB0AH 0DH ----------------------------------------- 0AH 0DHDB0AH 0DH Please input the number the number rang
include <> include <> struct Factorial { int digit struct Factorial next } void Input(int n) { cout << Please the n: cin>> n cout <<endl } void Output(struct Factorial firs
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