1解:x26A1O01第 2 章线性规划的图解法BC 36x1 : : : a.可行域为 OABCb.等值线为图中虚线所示c.由图可知最优解为 B 点最优解: x1=1215x2=最优目标函数值: : 69 72解:77 : a=This document was truncated here because it was created in the
1解:x26A1O01第 2 章线性规划的图解法BC 36x1Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsCreated with an evaluation co
: : : 第 4 章线性规划在工商管理中的应用1解:为了用最少的原材料得到 10 台锅炉需要混合使用 14 种下料方案方案123456规格7 : 2640177016511440合计剩余20005280220110044101090101042911209100140801420030053101900210519130902014980520 : 方案规格
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1解:x26A1O01第 2 章线性规划的图解法BC 36x1Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsa.可行域为 OABCb.等值线为图中虚线所示c.由图可知
8由图知有唯一最优解 x=(941)Tz=112由图知有无穷多最优解 x=α(41)(1- α)(52134)=(523 α 2134-9 α 4) z=14α∈[01]2210x39801001 -514单纯形表为:CBx3x4x5100 0 0 1 (1)0XBb-11200-1052M-12120XBb-2306120续表0x70-1101-1012-121203x
目录 TOC o 1-3 h z u l _Toc258875174 教材习题答案 PAGEREF _Toc258875174 h 1 l _Toc258875175 习题一 PAGEREF _Toc258875175 h 1 l _Toc258875176 习题二 PAGEREF _Toc258875176 h 28 l _Toc258875177 习题三
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习题五 用元素差额法直接给出表5-53及表5-54下列两个运输问题的近似最优解.表5-53B1B2B3B4B5AiA119161021918A21413524730A3253020112310A478610442Bj152535205表5-54B1B2B3B4AiA1538616A2107121524A31748930Bj20251015【解】表5-53Z=824表5-54 Z= 求表5-55及表
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