Class exerciserealize the logic function F with 3-to-8 decoder andlogic gatesF = ? (X,Y,Z) ( 1, 2, 4, 5 )Answer Key 1realize the logic function F with 3-to-8 decoder andlogic gates当使能端有效时Yi = Mi’
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Class exerciserealize the logic function F with 3-to-8 decoder andlogic gatesF = ? (X,Y,Z) ( 1, 2, 4, 5 )64 decoder 译码器Review of Last Class641Binary Decoder (二进制译码器)n-to- 2ndecoderThe mostmon
1已知:1810=000100102 求其相反数的补码表示: -1810=( 11101110 )22用最少位数写出-4910的二进制原码补码反码表示1110001100111110011103已知:100111012是某个数的补码表示问其用十进制的表达为 -994分别以符号-数值数制反码补码将-24表示为一个8位数100110
Exercise before class:1、If1810=000100102, Write the 8-bit two’splement representation for the decimal number: -1810=( )22、Write the signed-magnitude, two’splement, and ones’plement repres
class-exercises1、Write the 8421 binary- coded decimal representations for thedecimal numbers: 5862、Indicate whether or not overflow occurs when adding the following 8-bit two’splement numbers:Code
REVIEW OF LAST CLASS译码器编码器三态器件多路复用器奇偶校验器比较器加减器 标准MSI多路复用器74x151、 74x153、74x157 扩展多路复用器 利用多路复用器实现逻辑函数 多路分配器 利用带使能端的译码器 使能端作为数据输入端REVIEW OF LAST CLASS译码器编码器三态器件多路复用器奇偶校验器比较器加减器 奇校验:输入有奇数个1,输出为1 偶校验:输入有
Exercise of class如何变为D 锁存器Of lass classreview状态图S-R Flip-Flops (Latches)状态图J-K Flip-Flop状态图D Flip-Flops (Latches) 特征方程:Q* = D有使能端得D触发器:Q* = EN·D + EN’·Q T Flip-Flop说明: 传统中文教材中认为 T 触发器的特征方程为:Q* = T·Q’
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class-exercises1、1011100010112=8= 162、 ( 156 )10 = ()23、convert 03910 to a number in radixprecision must achieve10%。 ten minutesclass-exercises1、1011100010112= 5613 8= B8B 162、 ( 156 )10 = ( 10011100
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