class-exercises1、Write the 8421 binary- coded decimal representations for thedecimal numbers: 5862、Indicate whether or not overflow occurs when adding the following 8-bit two’splement numbers:Code
1已知:1810=000100102 求其相反数的补码表示: -1810=( 11101110 )22用最少位数写出-4910的二进制原码补码反码表示1110001100111110011103已知:100111012是某个数的补码表示问其用十进制的表达为 -994分别以符号-数值数制反码补码将-24表示为一个8位数100110
Exercise before class:1、If1810=000100102, Write the 8-bit two’splement representation for the decimal number: -1810=( )22、Write the signed-magnitude, two’splement, and ones’plement repres
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class-exercises1、1011100010112=8= 162、 ( 156 )10 = ()23、convert 03910 to a number in radixprecision must achieve10%。 ten minutesclass-exercises1、1011100010112= 5613 8= B8B 162、 ( 156 )10 = ( 10011100
Class exerciserealize the logic function F with 3-to-8 decoder andlogic gatesF = ? (X,Y,Z) ( 1, 2, 4, 5 )64 decoder 译码器Review of Last Class641Binary Decoder (二进制译码器)n-to- 2ndecoderThe mostmon
Class exerciserealize the logic function F with 3-to-8 decoder andlogic gatesF = ? (X,Y,Z) ( 1, 2, 4, 5 )Answer Key 1realize the logic function F with 3-to-8 decoder andlogic gates当使能端有效时Yi = Mi’
REVIEW OF LAST CLASS 1CMOS inverter常闭常开常闭常开VinP 沟道N沟道2CMOS 2-input NAND gateQ2CMOS inverter3PMOS: when G is 0, Switch on; when G is 1, Switch off;NMOS: when G is 1, Switch on; when G is 0, Switch
1?普通二进制编码器I40000101002优先二进制编码器 I600010011输出I411001100112控制端子:四位二进制优先编码器:输出(3)148(1) 148(2) 148(3) 148(4) (2)Y4 Y3 Y2 Y1 Y0(4)五位二进制优先编码器的逻辑关系:五位二进制优先编码器输出端子: 二二—十进制优先编码器——74LS147I70101111011C01010B(I8
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