第一章 行列式 1? 利用对角线法则计算下列三阶行列式? (1)? 解 ?2?(?4)?3?0?(?1)?(?1)?1?1?8 ?0?1?3?2?(?1)?8?1?(?4)?(?1) ??24?8?16?4??4? (2)? 解 ?acb?bac?cba?bbb?aaa?ccc
第一章 行列式 1? 利用对角线法则计算下列三阶行列式? (1)? 解 ?2?(?4)?3?0?(?1)?(?1)?1?1?8 ?0?1?3?2?(?1)?8?1?(?4)?(?1) ??24?8?16?4??4? (2)? 解 ?acb?bac?cba?bbb?aaa?ccc
第四章 Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
70 第五章相似矩阵及二次型1 试用施密特法把下列向量组正交化: (1); 解根据施密特正交化方法? , , ? (2)? 解根据施密特正交化方法? ? ? ? 2 下列矩阵是不是正交阵:(1); 解此矩阵的第一个行向量非单位向量, 故不是正交阵 (2)解该方阵每一个行向量均是单位向量, 且两两正交, 故为正交阵 3? 设x为n维列向量? xTx?1? 令H?E?2xxT? 证明H是对称的正交阵
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Word
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Words. To d
Created with an evaluation copy of Aspose.Words. To discover the full versions of our APIs please visit: :products.asposewordsPAGE Created with an evaluation copy of Aspose.Words. To d
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